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DarkKings799
05.05.2020 •
Mathematics
What is 3x-2y=11
X+2y=9 using substitution
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Ответ:
(5, 2)
Step-by-step explanation:
We have hte equations:
3x - 2y = 11
x + 2y = 9
Solving by substituting simply means writing one variable in terms of the other, plugging that into the other equation, and then solving.
x + 2y = 9
x = 9 - 2y
Plug in 9 - 2y for x in the first equation:
3x - 2y = 11
3 * (9 - 2y) - 2y = 11
27 - 6y - 2y = 11
27 - 8y = 11
16 = 8y
y = 2
Use this to find x:
x = 9 - 2y = 9 - 2 * 2 = 9 - 4 = 5
The solution is (5, 2).
Ответ:
1) P = 282m, A = 141m^2
2) P = 82.4in, A = 40in^2
3) P = 62.7m, A = 73.1m^2
Step-by-step explanation:
1) top:L=12m, W=3m, mid: l= 12m, w= 12-7 = 5m, bot: l=15m, w=3m
Perimeter= 2(lw)
P = 2(12x3) + 2(12x5) + 2(15x3)
P = 2(36) + 2(60) + 2(45)
P = 72 + 120 + 90
P = 282m
Area= lw
A = (12x3) + (12x5) + (15x3)
A = 36 + 60 + 45
A = 141m^2
2) Rectangle:l=7in, w=5in, Right Triangle:a=5-3=2in, b=12-7=5in
Perimeter= 2(lw) + (a+b+sqrt(a^2+b^2))
P = 2(7x5) + (2+5+sqrt(2^2+5^2))
P = 70 + 12.39
P = 82.4in
Area= lw + ((ab)/2)
A = (7x5) + ((2x5)/2)
A = 35 + 5
A = 40in^2
3) Semi-Circle: d=8m, r=8/2=4m, Right Triangle: a=8m, b=12m
Perimeter= pid + (a+b+sqrt(a^2+b^2))
P = 9pi + (8+12+sqrt(8^2+12^2))
P = 28.27 + 34.42
P = 62.7m
Area= (1/2)pir^2 + ((ab)/2)
A = (1/2)pir^2 + ((ab)/2)
A = (1/2)pi(4)^2 + ((8x12)/2)
A = 25.13 + 48
A = 73.1m^2