tfonarov
27.12.2019 •
Mathematics
What is 64x^6 + 27 written as a sum of cubes?
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Ответ:
(4x² + 3)(16
- 12x² + 9)
Step-by-step explanation:
A sum of cubes factors as
a³ + b³ = (a + b)(a² - ab + b²)
64
= (4x²)³ ⇒ a = 4x²
27 = 3³ ⇒ b = 3
Hence
64
+ 27
(4x² + 3)((4x²)² - (4x² × 3) + 3²)
= (4x² + 3)(16
- 12x² + 9)
Ответ: