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tamya12234
26.06.2019 •
Mathematics
What is a polynomial function in standard form with zeros 1, 2, -3, and -1? g(x)=x^4+x^3-7x^2-x+6 g(x)=x^4+x^3+7x^2-x+6 g(x)=x^4+x^3-7x^2-x-6 g(x)=x^4-x^3-7x^2-x+6
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Ответ:
[tex] g(x)=x^4+x^3-7x^2-x+6[\tex]
Step-by-step explanation:
Since, According to the question,
1, 2, - 3 and - 1 are zeros of the function g(x),
Also, function has the degree 4.
Thus, [tex]g(x) = (x-1)(x-2)(x+3)(x+1)[\tex]
[tex] g(x) = (x-1)(x-2)(x^2+4x+3)[\tex]
[tex] g(x) =(x-1)(x^3+4x^2+3x-2x^2-8x-6)[\tex]
[tex] g(x) =(x-1)(x^3+2x^2-5x-6)[\tex]
[tex] g(x) = x^4+x^3-7x^2-x+6[\tex]
Ответ:
omg make a long story short, it is 4.5.
Step-by-step explanation: