What is an equation of the line that passes through (6,-1) and is parallel to the line x-3y = 3

a=-3

Step-by-step explanation:

find the equation of the line parallel to the line x−3y=3 passing through the point (6,−1).

The equation of the line in the slope-intercept form is y=x3−1.

The slope of the parallel line is the same: m=13.

So, the equation of the parallel line is y=x3+a.

To find a, we use the fact that the line should pass through the given point: −1=(13)⋅(6)+a.

Thus, a=−3.

The answer is A, 651. You would first start by multiplying the number of students, 1,860, by 45%, or .45. You'd come out with the answer of 837. You would then add 837 and 372 together to get a sum of 1,209. Finally, you would subtract 1,209 from the total number of students, which was 1,860 and get an answer of 651. I hope this helped you understand how a problem like this should be worked out!