What is an equation of the line that passes through the points (3, 1)(3,1) and (6, 6)(6,6)? Put your answer in fully reduced form.

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  y = (5/3)x -4

Step-by-step explanation:

The 2-point form of the equation of a line can be written as ...

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (6-1)/(6-3)(x -3)+1 . . . . fill in given point values

  y = 5/3(x -3) +1 . . . . . . . .  simplify

  y = 5/3x -5 +1 . . . . . . . . . .eliminate parentheses

  y = 5/3x -4 . . . slope-intercept form of equation