What is equation of the line that passes through the point (-3,8) and has an undefined slope

The equation of line that passes through point (-3, 8) and has an undefined slope is x = -3

Solution:

Given that we have to find the equation of line that passes through point (-3, 8) and has an undefined slope

Since the line has an undefined slope. This informs us that it is a vertical line parallel to the y-axis and passing through all points in the plane with the same x-coordinate.

If the slope of the line is undefined, then, by definition the line is a vertical line.

For a vertical line, the value of  x  is the same for each and every value of  y

Given point is (x, y) = (-3 , 8)

Because the value of  x  in the point provided in the problem is -3, we get

Equation of line is : x = -3

Explanation with Proof is given below.

Step-by-step explanation:

Given:

In  Δ ABC,

m∠ A = 59°

m∠ B = 37°

In Δ A'B'C'

m∠ A' = 59°

m∠ C' = 84°

To Prove:

Δ ABC ~ Δ A'B'C'

Proof:

In  Δ ABC we have,

m∠ A + m∠ B + m∠ C = 180° {Angle Sum Property of Triangle}

Substituting the given values we get

Now,

In  Δ ABC and Δ  A'B'C'

∠ A ≅ ∠ A'     …………..{measure of each angle is 59°}

∠ C ≅ ∠ C'     ……….{measure of each angle is 84°}

Δ ABC ~ Δ A'B'C'  ….{ By Angle-Angle Similarity Postulate} Proved