tbenjamin1299
10.03.2020 •
Mathematics
What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 3? Amplitude = 4; period = π; phase shift: x equals pi over two Amplitude = −4; period = 2π; phase shift: x equals pi over two Amplitude = 4; period = π; phase shift: x equals negative pi over two Amplitude = −4; period = 2π; phase shift: x equals negative pi over two
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Ответ:
The correct option is option (c)
Therefore amplitude = 4, period= π and
Step-by-step explanation:
Amplitude: The amplitude of a wave is a maximum displacement of a particle from its rest position
Period: The ratio of wavelength to the velocity.
Phase shift: The phase shift represents the amount a wave has shifted horizontally from the the usual position.
The equation of a wave is
f(x) = a sin(bx - c)+d
Where
amplitude = |a|
Given equation of wave is
f(x) = -4sin (2x + π) -3
Here a=-4, b=2, c = -π, d = -3
Amplitude = |-4| = 4
Therefore amplitude = 4, period= π and
Ответ:
sorry but I don't know but good luck I hope you get the answer