Mathematics: What is the area of a rectangle with vertices at (2, 3), (7, 3), (7, 10), and (2, 10)? a. 44 units2 b. 30 units2 c. 24 units2 d. 35 units2

13 = xStep-by-step explanation: = 6x + 42 = 8x + 1642 = 2x + 16 = 13 = x...

What is the area of a rectangle with vertices at

Ответ:

ultimatesaiyan

03.01.2022

D 35 units squared. If you would graph it on a piece of graph paper or look at the points one side would be the difference between 10 and 3 and the other side would be the difference between 7 and 2. Then taking those totals multiple them together to get the area

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Ответ:

boo3972

03.01.2022

Mathematics

The correct option is (d) 35 units².

Step-by-step explanation: We are given to find the area of a rectangle with vertices at the points (2, 3), (7, 3), (7, 10), and (2, 10).

Let A(2, 3), B(7, 3), C(7, 10), and D(2, 10) represents the co-ordinates of the vertices of the given rectangle.

Then, the lengths of the sides AB, BC, CD and DA ca be calculated using distance formula as follows :

$AB=\sqrt{(7-2)^2+(3-3)^2}=\sqrt{25+0}=\sqrt{25}=5~\textup{units},\\\\BC=\sqrt{(7-7)^2+(10-3)^2}=\sqrt{0+49}=\sqrt{49}=7~\textup{units},\\\\CD=\sqrt{(2-7)^2+(10-10)^2}=\sqrt{25+0}=\sqrt{25}=5~\textup{units},\\\\DA=\sqrt{(2-2)^2+(3-10)^2}=\sqrt{0+49}=\sqrt{49}=7~\textup{units}.$