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roderickhinton
17.07.2020 •
Mathematics
What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.
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Ответ:
Area of the rhombus ABCD = 16 square units
Step-by-step explanation:
Area of a rhombus =![\frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})](/tpl/images/0708/2876/74848.png)
From the graph attached,
Diagonal 1 = Distance between the points A and C
Diagonal 2 = Distance between the points B and D
Length of a segment between (x₁, y₁) and (x₂, y₂) =![\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }](/tpl/images/0708/2876/eba16.png)
Diagonal 1 (AC) =
= 4 units
Diagonal 2(BD) =
= 8 units
Now area of the rhombus ABCD =![\frac{1}{2}(\text{AC})(\text{BD})](/tpl/images/0708/2876/615ad.png)
=![\frac{1}{2}\times 4\times 8](/tpl/images/0708/2876/cb774.png)
= 16 units²
Therefore, area of the given rhombus is 16 units².
Ответ:
Juan b/c her slope goes up slower than Rita