Mathematics: What is the area of the shaded region?

What is the area of the shaded region? - id5134223, fernandaretanaoxwln0

Ответ:

kpopqueen0

18.01.2022

Mathematics

$\large \boxed{\text{21.86 ft}^{2}}$

Step-by-step explanation:

Area of shaded region = area of square - area of semicircle

1. Area of square

A = s² = (6 ft)² = 36 ft²

2. Area of semicircle

Area of circle = πr²

Area of semicircle = ½πr²

r = 3 ft, so

A = ½π(3 ft)² = ⁹/₂π ft³

3. Area of shaded region

A = area of square - area of semicircle

$\begin{array}{rcl}A & = & \mathbf{\left(36 - \dfrac{9}{2} \pi \right )} \textbf{ ft}^{\mathbf{2}}\\\\ &\approx & \left (36 - 14.1372\right)\text{ ft}^{2}\\ & \approx & \mathbf{21.86}\textbf{ ft}^{\mathbf{2}} \\\end{array}\\\text{The area of the shaded figure is approximately $\large \boxed{\textbf{21.86 ft}^{\mathbf{2}}}$}$

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Ответ:

rina62

07.09.2020

Mathematics

Probability formula is

number of favorable outcomes/ total number of outcomes.

50 + 32 + 40 + 24 + 30+ 8 + 6 + 8 + 2 = 200

It is given bit I just want to give a working exprencje.

So we get 200 days.

Which is the total number of outcomes,

A. We must find the number of outcomes that gives us 0 defective parts.

There is 50 of them so

P( 0 defective parts) is

$\frac{50}{200} = 0.25$

1/4

B. At least one defective part, is the complement to zero defective part. If we find the probability of the something have zero parts, etc, that is the component to something thar has at least one.

Probability for complement is

$p {}^{c} = 1 - p(e)$