What is the common factor of 34m and 16m^2

125 times brighter

Step-by-step explanation:

If the dazzling day have a value of 5 in your scale, and a dim day, a value of 2, there are 5-2 = 3 category increases between them. Now, every category is 5 times brighter than its immediate predecessor so:

B₃ =5*B₂;

B₄ =5*B₃;

B₅ =5*B₄;

Replacing, we get:

B₅ = 5*(5*(5*B₂));

This is:

B₅ = 5³*B₂;

B₅ = 125*B₂