Mathematics: What is the distance from Cto D? 5 4 D(5,3) 3 2 1 5 1 2 3 C(2, -1 -2 3 -4 -5 OA. 5 units B. 25 units C. 7 units D. 1 unit

What is the distance from Cto D? 5 4 D(5,3) 3 - id545332113625449, am2016832

AjTruu2880

04.07.2021

Given:

The two points C(2,-1) and D(5,3) on a coordinate plane.

To find:

The distance from C to D.

Solution:

The distance between two points is defined by the distance formula.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The two points are C(2,-1) and D(5,3). Using the distance formula, we get

$CD=\sqrt{(5-2)^2+(3-(-1))^2}$

$CD=\sqrt{(3)^2+(3+1)^2}$

$CD=\sqrt{(3)^2+4^2}$

On further simplification, we get

$CD=\sqrt{9+16}$

$CD=\sqrt{25}$

CD=5

The distance from point C to D is 5 units. Therefore, the correct option is A.

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hebrew1148

12.07.2020

Step-by-step explanation:

Given is a quadratic equation in the variable x.

5x^2-1.5x-0.5=0

We have to solve this equation using graphing calculator.

Without graph also we can factorize and solve the equation

For factorization, let us have all coefficients as integers.

The given equation can be written as

$50x^2-15x-5=0\\[tex]10x^2-3x-1=\\10x^2-5x+2x-1=0\\]$ by dividing by common factor 5

Now factorization can be done as

$=10x^2-5x+2x-1\\=5x(2x-1)+1(2x-1)\\=(5x+1)(2x-1)$

Equate each factor to 0 to get

x=0,5 or x=-0.2

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