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The three even integers are 66, 68 and 70

Solution:

Let the three consecutive even integers be x, x + 2, x + 4

Let the first integer be x

Let the second integer be x + 2

Let the third integer be x + 4

Given that, sum of the first and third of three consecutive integers is 136

Sum of first and third integer = 136

x + x + 4 = 136

2x + 4 = 136

2x = 136 - 4

2x = 132

x = 66

Thus the consecutive integers are:

first even integer = x = 66

second even integer = x + 2 = 66 + 2 = 68

third even integer = x + 4 = 66 + 4 = 70

Thus the three even integers are 66, 68 and 70