What is the equation for (-3,3) and (1,1)

The correct equation for (-3, 3) and (1, 1) is y = -1/2x + 1.5.

Step-by-step explanation:

To find the slope (or m), you put the rise (y-axis) over the run (x-axis). You would then put it in Slope-Intercept form: y = mx + b.

Starting at (1, 1), you rise up 2, and run 4. (Although distance is never negative, that's a -4) The slope (m) would be -0.5, which is the same as -1/2.

So far you have y = -1/2x, which is not the full equation.

You would then need the initial value (or y-intercept) of the linear equation. I suggest you draw a line for the two points. Once you do that, start at the origin of the graph - (0, 0) - and rise up until you get to the line, (0, 1.5). You rise up 1.5, so the initial value is 1.5.

Your ending equation would be y = -1/2x + 1.5.

Hope this helps,

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