Mathematics: What is the equation for the hyperbola shown? x^2/60^2-y^2/11^2=1 x^2/11^2-y^2/60^2=1 y^2/60^2-x^2/11^2=1 y^2/11^2-x^2/60^2=1

okStep-by-step explanation::v...

What is the equation for the hyperbola shown?

ahmed5774

23.01.2022

The answer to your question is $\frac{x^{2}}{60^{2}} - \frac{y^{2}}{11^{2}} = 1$

Step-by-step explanation:

Data

From the graph

Horizontal hyperbola

Center (0, 0)

a = 60 a is the distance from the Center to the Vertex

b = 11 b is the distance from the Center to the endpoint of the conjugate

axis.

The Equation for a horizontal hyperbola

$\frac{(x- h)^{2} }{a^{2}} - \frac{(y - k)^{2}}{b^{2}} = 1$

h = 0, k = 0

-Substitution

$\frac{x^{2}}{60^{2}} - \frac{y^{2}}{11^{2}} = 1$

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ptrlvn01

23.01.2022

Option 1

Step-by-step explanation:

(x - 0)²/60² - (y - 0)²/11² = 1

x²/60² - y²/11² = 1

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ramanpreet

31.03.2020

Step-by-step explanation:

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