What is the equation for this graph’s lone of best fit.
this is due today pls help

I don't know if your question is multiple choice or not but here's a close estimate to what it should be.

y =  

Step-by-step explanation:

Obviously at a drop of 0 height there would be 0 rebound height so your y-intercept has to be 0.

As for the slope of the line I used the point at 2.5 and 3.

Here are the coordinates (2.5, 1.25) and (3, 1.625)

Find the average rate of change as you see below

1.625 - 1.25 = .375

3 - 2.5 = .5

.375 / .5 = .75 or 3x/4

The points aren't exactly on the line and the graph isn't 100% linear so obviously the equation is not 100% precise. The slope should very close to 0.75 or 3/4.

Step-by-step explanation:

The given equations are:

                                           Equation 1

                                               Equation 2

Multiplying the Equation 2 with -2, we get:

                                         Equation 3

Adding Equation 1 and Equation 3, we get:

Using this value of y, in either of the equations will give the relation independent of y.

Using the value of y in Equation 2, we get: