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beccahmaarie
25.04.2020 •
Mathematics
What is the equation of the circle with radius, r = 11 , and the center at (0, - 7)
A. x ^ 2 + (y + 7) ^ 2 = 121
B. (x + 7) ^ 2 + y ^ 2 = 121
C. (x - 7) ^ 2 + y ^ 2 = 11
D. x ^ 2 + (y - 7) ^ 2 = 11
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Ответ:
A
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Given (h, k) = (0, - 7) and r = 11, then
(x - 0)² + (y - (- 7))² = 11², that is
x² + (y + 7)² = 121 → A
Ответ:
D, if there are choices
Step-by-step explanation:
;)