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yrkfred1440
26.01.2020 •
Mathematics
What is the equation of the following line written in slope-intercept form?
a.) y =3/2 x -13/3
b.) y =2/3 x -13/3
c.) y =-2/3x - 13/3
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Ответ:
Ответ:
WE use given graph to find equation of the line
one point on the graph is (-5,-1)
other point on the graph is (-2,-3)
We need to frame equation y =mx+b
Lets find slope using (-5,-1) and (-2,3)
Now we find y intercept b using (-5,-1)
y=mx+b
Subtract 10/3 on both sides
So equation of the line is![y=\frac{-2}{3}x-\frac{13}{3}](/tpl/images/0471/6415/bdefd.png)
Ответ: