Mathematics: What is the equation of the line first written in point slope form and then written in slope intercept form? show how you did it

What is the equation of the line first written

Ответ:

Jaylanbeadles

11.03.2022

Mathematics

We have the points (3, 21) and (6, 12).

The slope-intercept form: y = mx + b.

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute:

$m=\dfrac{12-21}{6-3}=\dfrac{-9}{3}=-3\\\\y-21=-3(x-3)\qquad|\text{use distributive property}\\\\y-21=(-3)(x)+(-3)(-3)\\\\y-21=-3x+9\qquad|\text{add 21 to both sides}\\\\y=-3x+30$

point-slope form: y - 21 = -3(x - 3)slope-intercept form: y = -3x + 30

0,0(0 оценок)

Ответ:

aeverettpdzrvo

21.11.2020

Mathematics

The answer would be A. 1 1/5

Step-by-step explanation:

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!

0,0(0 оценок)

What is the equation of the line first written in point slope form and then written in slope intercept form? show how you did it

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question