What is the equation of the line of the axis of symmetry of the quadratic function, y=3x^2-x+2?

a) x= -3/2
b) x= -1/6
c) x=1/6
d) x=3/2

Y=3x^2-x+2

Find when the velocity, dy/dx, is equal to zero, this value of x will represent the axis of symmetry for a quadratic because all quadratics have a constant acceleration, and thus when dy/dx=0, y(x), is at either a global maximum or minimum... 

dy/dx=6x-1

6x-1=0

6x=1

x=1/6

So the vertical line x=1/6 is the axis of symmetry.

The answer appears to be three hundred eighty five can't wait to get those points! Hope your happy with your answer!