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loganharper992
01.10.2019 •
Mathematics
What is the equation of the line that passes through the point (3,0) and is perpendicular to the line 2x-y=5?
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Ответ:
Turn our given equation into y=mx+b form.
2x - y = 5
Subtract 2x from both sides.
-y = -2x + 5
Divide both sides by -1.
y = 2x - 5
So, our slope is 2.
However, because our equation is perpendicular, we must find the negative reciprocal of 2.
Slope₁ = 2
Slope₂ = -1/2
y - y₁ = m(x - x₁) (3, 0)
Plug everything in.
y - 0 = -1/2(x - 3)
y = -1/2x + 3
~Hope I helped!~
Ответ:
Step-by-step explanation:
So we multiply 7 by 4, and get 28. Then we multiply 2 by 12, and get 24. Next we give both terms new denominators 12 × 4 = 48.