deku6
05.07.2020 •
Mathematics
What is the equation of the line that passes through the point (-2,14) and is perpendicular to the line with the following equation?
y = -x-1
OA
y =
OB
y =
- + 9
o + 16
1 - 12
Oc.
y =
OD.
y =
+ 19
Solved
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Ответ:
y = x + 16
Step-by-step explanation:
Step 1: Find slope of perpendicular line
Take the negative reciprocal of the 1st line
m = 1
Step 2: Find b
y = x + b
14 = -2 + b
b = 16
Step 3: Write equation
y = x + 16
Ответ:
y = x + 16
Step-by-step explanation:
Given the equation y = -x - 1, we see that the slope (the coefficient of the x term) is -1. A line perpendicular to this one has a slope which is the negative reciprocal of the given equation: +1.
Using the point-slope formula for the equation of a straight line, we get:
y - 14 = +1(x + 2), or y - 14 = x + 2, or y = x + 16
Ответ:
5n+7
Step-by-step explanation:
12+5=17(5n)
5+7=12(+7)
Hope this will help ya!