What is the equation of the quadratic graph with a focus of (1 ,3) and a directrix of y=1? hint: y=a (x*h)^2 +k, a=1/4p (x-x1)^2 + (y-y2)^2

Check the picture below.

now, we know the directrix is at y = 1, and the focus point is at 1,3, well, notice the picture, the distance between those fellows is just 2 units.

the vertex is half-way between those fellows, therefore, the vertex will be at 1,2.

the distance "p", from the vertex to either the directrix or focus, is really just 1 unit.  Since the focus point is above the directrix, is a vertical parabola, and it opens upwards, like in the picture, and since it opens up, the "p" value is positive, or +1.

Break the figure into a parallelogram and a triangle. Find the area of each using the formulas A=bh and A=1/2bh. The sum of the areas is the area of figure.