What is the expected value for the binomial distribution below?

1/3125
4/625
32/625
128/625
256/625
1024/3125

999.224

Step-by-step explanation:

Expected value = Summation of (x•px)

px is addressed as pdf (probability distribution function)

x px. x•px

1. 1/3125. 1/3125

20. 4/625. 16/125

160. 32/625. 1024/125

640. 128/625. 16384/125

1280. 256/625 65536/125

1024. 1024/3125. 335.544

total:. 1. 999.224

taking my pdf as x/3125

One 3(2x + 10) - 2(x - 2) - 59  = 3

Step-by-step explanation:

First, break up 7 into two parts:

3 + 4 = 7

Then, replace 7 with x:

3 + 4 = x

Then, create more complexity:

3 + 21 - 14 = x

21-14 = x - 3

3(x) - 2(x) - x = 3

Drop the last -x and add a constant:

3(2x + 10) - 2(x - 2) - 59  = 3

Proof:

3(2(7) + 10) - 2(7 - 2) - 59 = 3

3(14 + 10) - 2(5) - 59 = 3

3(24) - 10 -

72 - 10 - 59 = 3

62 - 59 = 3

3 = 3

Hope this helps! Have an awesome day! :-)