What is the factorization of the polynomial 3x^2 + 11x + 6 ? show how you got the answer, you!

I used the generic rectangle/diamond method, although the quadratic formula would work just as well with a=3, b=11, c=6.  Put that into the quadratic formula to get that your factors are x = -2/3 and -3.  Putting those into factorization form you get the 2 factors as (3x+2)(x+3)

f(1) = 13

Step-by-step explanation:

f(n+1)=f(n)+3

then

f(n) = f(n+1) - 3

then

f(3)=f(4)-3 = 22 - 3 = 19

f(2)=f(3)-3 = 19 - 3 = 16

f(1)=f(2)-3 = 16 - 3 = 13