Mathematics: What is the fifth term of the recursive formula a(n)=2a(n-1)-1 with the first term of 3? a. 7 b. 17 c. 33 d. 65

What is the fifth term of the recursive formula

Ответ:

mamieengler

13.03.2022

$\bf \begin{array}{ccll}
n&term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&a(1)&3\\
2&a(2)&2a(2-1)-1\\
&&2a(1)-1\\
&&2(3)-1\\
&&5\\
3&a(3)&2a(3-1)-1\\
&&2a(2)-1\\
&&2(5)-1\\
&&9\\
4&a(4)&2a(4-1)-1\\
&&2a(3)-1\\
&&2(9)-1\\
&&17\\
5&a(5)&2a(5-1)-1\\
&&2a(4)-1\\
&&2(17)-1\\
&&33
\end{array}$

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Ответ:

aletadaboss

02.12.2020

Mathematics

a=7

b=22

Step-by-step explanation:

mean=9

so sum of numbers=9×4=36

also

2+5+a+b=36

a+b=36-7=29

number of terms=4

median =(2nd+3rd)/2

(5+a)/2=6

5+a=12

a=12-5=7

7+b=29

b=29-7=22

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What is the fifth term of the recursive formula a(n)=2a(n-1)-1 with the first term of 3? a. 7 b. 17 c. 33 d. 65

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