What is the following product? assume x ≥ 0\sqrt[3]{x^{2}

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Geo777

10.03.2022

Mathematics

For this case we must multiply the following expression:

$\sqrt [3] {x ^ 2} * \sqrt [4] {x ^ 3}$

By definition of properties of otencias and roots we have:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

We rewrite the terms of the expression:

$\sqrt [3] {x ^ 2} = (x ^ 2) ^ {\frac {1} {3}} = (x ^ 2) ^ {\frac {4} {12}}\\\sqrt [4] {x ^ 3} = (x ^ 3) ^ {\frac {1} {4}} = (x ^ 3) ^ {\frac {3} {12}}$

So, we have:

$(x ^ 2) ^ {\frac {4} {12}} * (x ^ 3) ^ {\frac {3} {12}} =$

Applying the above definition we have:

$\sqrt [12] {(x ^ 2) ^ 4} * \sqrt [12] {(x ^ 3) ^ 3} =$

We multiply the exponents:

$\sqrt [12] {x ^ 8} * \sqrt [12] {x ^ 9} =$

We combine using the product rule for radicals.

$\sqrt [12] {x ^ 8 * x ^ 9} =$

By definition of multiplication properties of powers of the same base, we put the same base and add the exponents:

$\sqrt [12] {x ^ {8 + 9}} =\\\sqrt [12] {x ^ {17}} =\\\sqrt [12] {x ^ {12} * x ^ 5} =\\x \sqrt [12] {x ^ 5}$

Option C

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What is the following product? assume x ≥ 0\sqrt[3]{x^{2} } . \sqrt[4]{x^{3} }a. x\sqrt{x}b. \sqrt[12]{x^{5} }c. x(\sqrt[12]{x^{5} } )d. x6

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