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ImmortalEnigmaYT
17.07.2019 •
Mathematics
What is the following quotient 6-3(^3√6)/^3√9
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Ответ:
Step-by-step explanation:
We first rationalize the denominator. This means we multiply the numerator and denominator by a factor that will make the denominator a whole number.
Our denominator is
; this can also be written as
.
For 9 to be a whole number, its exponent must be a whole number. We want to add 2/3 to the exponent of 9 on the bottom; this means we multiply by
:
On the numerator, this gives us:
6(9^(2/3))-3(6^(1/3))(9^(2/3))
=![6\sqrt[3]{9(9)} -3\sqrt[3]{2(3)}(\sqrt[3]{9(9)}) \\\\=6\sqrt[3]{3(3)(3)(3)}-3\sqrt[3]{2(3)(3)(3)(3)(3)}\\\\=6(3)\sqrt[3]{3}-3(3)\sqrt[3]{2(3)(3)}\\\\=18\sqrt[3]{3}-9\sqrt[3]{18}](/tpl/images/0098/2597/300c9.png)
On the denominator, we will have:
(9^(1/3))(9^(2/3)) = 9^(3/3) = 9^1 = 9
This gives us:
Ответ:
Explanation:
1) Rationalize by multiplying numerator and denominator by
2)
3) Due the operations
Ответ:
i think it would be w=p/2-l
Step-by-step explanation:
sorry if im wrong