What is the lateral surface area of the figure below?

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Ответ:

dessssimartinez6780

07.10.2021

Mathematics

The area of the rectangle is 60 square units.

Step-by-step explanation:

The given figure represents a rectangle with vertices (-5,2), (-7,-2), (5,-8) and (7,-4).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Find the distance between (-5,2) and (7,-4), to calculate the length of the rectangle.

$l=\sqrt{(7-(-5))^2+(-4-2)^2}=\sqrt{(12)^2+(-6)^2} =\sqrt{144+36}=\sqrt{180}$

Find the distance between (7,-4) and (5,-8), to calculate the width of the rectangle.

$w=\sqrt{(5-7)^2+(-8-(-4))^2}=\sqrt{(-2)^2+(-4)^2}=\sqrt{4+16}=\sqrt{20}$

The area of rectangle is

$A=l\times w$

$A=\sqrt{180}\times \sqrt{20}$

$A=\sqrt{3600}$

A=60

Therefore the area of the rectangle is 60 square units.

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