What is the length of arc QR?
A. 1/3 π
B. 10/3 π
C. 5/3 π
D. 20/3 π

D, 20/3 π

Step-by-step explanation:

10x2=20cm (the diameter)

20xπ = the circumference

120 = 1/3 of 360

20π x 1/3 = 20π/3 or 20/3π

The value of x is 9.

Solution:

AB is a tangent and BD is the secant.

AB = 12, BC = 9 and CD = x

BD = BC + CD

BD = 9 + x

The product of the lengths of the secant segment and its external segment equals the square of the length of the tangent segment.

Subtract 81 from both sides.

Divide by 9 on both sides.

The value of x is 9.