What is the midpoint of the line segment graphed below?
(6,-8)
(1, -1)

The midpoint is

Step-by-step explanation:

The formula for finding the midpoint of a line is

This means the formula for the x-coordinate of the midpoint is , and the formula for the y-coordinate of the midpoint is .

First, let's find the x-coordinate of the midpoint:

Add the two x values of the coordinates given, then divide that by two.

Next, let's find the y-coordinate of the midpoint:

Add the two y values of the coordinates given, then divide that by two.

Therefore, the midpoint of the line segment is . Hope this helps!

a) E = 2.30×10^6N/C

Direction =+E . It will point radically outward

b)E = -3.3×10^5NC^-1

Direction =- E,it will point radically inwards

Explanation:

Magnitude E at 4.7cm= 0.047m

E= wavelength 1/2×3.142×rEo

E= (6.0×10^-6)/2×3.142×0.047×(8.85×10^-12)

E= (6.0×10^-6)/(2.6×10^-12)

E= 2.30×10^6N/C

Direction= +E shows it will point radically outward.

b) Magnitude E at 8.1cm=0.081

E= (wavelength 1+ wavelength 2) / 2×3.142rEo

E= [(6.0×10^-6)-(7.5×10^-6)]/(2×3.142×0.081×(8.84×10^-12)

E= -(1.5×10^-6)/(4.5×10^-11)

E= -3.3×10^5N/C

Direction =I-A it will point inwards