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jessezarate4513
27.08.2019 •
Mathematics
What is the minimum value for h(x)=x2−16x+60?
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Ответ:
First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16
at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.
Just plug in 8 to the original equation to find the answer for the minimum value.
Ответ:
is there anther way you can put the pic i cant see