What is the original slope and what is the perpendicular

Ответ:

dontrailgrant98

06.02.2022

green line:

rise= -6

run= 3

rise/run = slope

therofore the slope = -6/3 = -2

blue line:

rise=3

run=6

rise/run = slope

therofore the slope = 3/6 = 1/2

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user11883661

06.02.2022

- 2 and $\frac{1}{2}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 3, 5) and (x₂, y₂ ) = (0, - 1) ← 2 points on the green line

m = $\frac{-1-5}{0+3}$ = $\frac{-6}{3}$ = - 2

Repeat with (x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (6, 0) ← 2 points on the blue line

m = $\frac{0+3}{6-0}$ = $\frac{3}{6}$ = $\frac{1}{2}$

Since the product of the slopes = - 2 × $\frac{1}{2}$ = - 1

Then the lines are perpendicular

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evy22

16.04.2020

C) 3x^2 + 20x + 12 = 0

Step-by-step explanation: Because it is the right answer

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