Mathematics: What is the point slope of the equation for a line with a slope of 6/19 that passes through the point (-1 , 7/5) ?

What is the point slope of the equation for a line

lilroach4

11.03.2022

ANSWER

The point slope form is $y-\frac{7}{5}=\frac{6}{19}(x+1)$

EXPLANATION

The point slope form of the equation of a straight line is given by the formula;

y-y_1=m(x-x_1) .

Where is the slope of the straight line and the point (x_1,y_1) lies on the line.

We were given the slope to be $\frac{6}{19}$ . This means that $m=\frac{6}{19}$ .

We were also given that the point $(-1,\frac{7}{5})$ lies on the line.

We substitute all these values in to the above equation to obtain,

$y-\frac{7}{5}=\frac{6}{19}(x--1)$

This simplifies to

$y-\frac{7}{5}=\frac{6}{9}(x+1)$

The correct answer is C

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