What is the polar form of Negative 2 StartRoot 3 EndRoot minus 6 i?

4√3 [cos (2π/3) + isin(2π/3)]

Step-by-step explanation:

We are to write out the polar form of:

-2√3 - 6i

In Mathematics:

The polar form of a given complex number a + bi is given as r[cos(θ)+isin(θ)],

where r =√a²+b²and

θ = arc tan (b/a) when a is > 0

or arc tan (b/a) + π or arc tan (b/a) + 180 when a is < 0

From the above question:

-2√3 - 6i

We have that

a = −2√3 and b = −6

Hence:

r =√a²+b²

r = √(-2√3)² + (-6)²

r = √(4 × 3) + 36

r = √12 + 36

r = √48

r = √16 × 3

r = 4√3

a is < 0

Hence,

θ = arc tan (b/a) + π

θ = arc tan (-6/-2√3) + π

θ = 2π/3

Substituting 4√3 for r and 2π/3 for θ in:

r[cos(θ)+isin(θ)]

-2√3 - 6i = 4√3 [cos (2π/3) + isin(2π/3)]

The correct answer is volt.

Step-by-step explanation:

Potential difference is the work done in bringing the charge from one point to another.

Or

Potential difference between the two points is defined as the change in the potential energy when the charge is moved from one point to other point.

The expression for the potential difference in terms of  work done and charge is as follows;

Here, is the change in the potential difference, W is the work done and q is the charge.

The SI unit of potential difference is volt.

1 volt is defined as the one joule of work done in bringing one coulomb charge from one point to another.

Therefore, potential difference is measured in units called volt.