Mathematics: What is the product of (2p + 7)(3p2 + 4p – 3)? 6p3 + 29p2 – 34p + 21 6p3 + 29p2 – 22p + 21 6p3 + 29p2 + 22p – 21 6p3 + 29p2 + 34p – 21

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What is the product of (2p + 7)(3p2 + 4p – 3)? - id273243633472389, rainbowsauxe

Ответ:

arayah1888

08.01.2022

Mathematics

6p^3 + 29p^2 + 22p – 21

Step-by-step explanation:

The given expression : (2p + 7)(3p^2 + 4p - 3)

To find the product, we need to use the distributive property.

The distributive property is given by :-

a(b+c)=ab+ac

Then , the product will become:

$(2p + 7)3p^2 + (2p + 7)4p - (2p + 7)3\\\\=\\\\=(2p*3p^2 + 7*3p^2)+(2p*4p + 7*4p)-(2p*3 + 7*3)\\\\=6p^{2+1}+21p^2+8p^{1+1}+28p-6p-21........\text{Since }a^ma^n=a^{m+n}\\\\=6p^3+21p^2+8p^2+22p-21\\\\=6p^3 + 29p^2 + 22p - 21$

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Ответ:

Peggy1621

16.03.2020

Mathematics

Step-by-step explanation:

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What is the product of (2p + 7)(3p2 + 4p – 3)?

6p3 + 29p2 – 34p + 21
6p3 + 29p2 – 22p + 21
6p3 + 29p2 + 22p – 21
6p3 + 29p2 + 34p – 21

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