What is the remainder when (x^3+1) is divided by (x^2-x+1)?

A; x + 1

Step-by-step explanation:

Since the viniculum in a fraction represents division, we can rewrite the expression like this:

We can already see that could be factored:

Since anything with a "one" as its base will remain one, we can rewrite:

Now, we can apply the "sum of cubes" formula:

Cancelling out!

Thusly, you are correct and the remainder is .

Hope this helps! ((:

(4) 2^3 · 5

Step-by-step explanation:

I'm pretty sure you meant to put Select the GCF of 2^5 · 5 · 11 and 2^3 · 5^2 · 7

In this case, to find your answer, you would need to compare each individual factor of the polynomial. The GCF of 2^5 and 2^3 is 2^3. The GCF of 5 and 5^2 is 5. 7 and 11 do not have a GCF since they are both prime numbers. So, your answer would be 2^3 · 5