What is the second term of (x+3) a. x^9 b. 3x^9 c. 9x^8 d. 27x^8

D. 27x^8

Step-by-step explanation:

what is the second term of (x+3)^9???

A. x^9

B. 3x^9

C. 9x^8

D. 27x^8

this expansion can be solved using pascal triangle or

the binomial expansion can be designated with the formula usin combination rule.

n=number of terms

let n=9

r=0

P=x

Q=3

P decreases n value while Q increases

n!/(n-r)!*r!

for the first term

9!/(9-0)!0! *x^9*3^0

for the second term

9!/(9-1)!1! *x^8*3^1

9*x^8*3

D. 27x^8

I’m guessing it’s A because what u would have to do is multiply 9 by 3 and then 9 by x which would come to 9x + 27

You first find the area of one piece. The small squares are 4 and there are two so you have 8 so far. The length of the rectangles are 4 and using the width of the square (2) and you multiply, then you get 8 per rectangle, there are 4 rectangles so the total area of the rectangles are 32 adding the 8 from the squares, you get 40 square feet. (2*2*2)+(4*2*4)=40 square feet. Hope this helped!