Mathematics: What is the solution for 8y ≥ 56

The position of point B is:Step-by-step explanation:Let be , and . The ratio is:After some algebraic handling:The position of point B is:...

What is the solution for 8y ≥ 56 - id85613707609, ethanyayger

QueenNerdy889

11.06.2021

y ≥ 7

Step-by-step explanation:

$8y \geq 56\\\\\frac{8y\geq 56}{8}\\\\\boxed{y\geq7}$

Hope this helps.

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faithforlife3573

26.10.2021

The position of point B is:

$(x_{3}, y_{3}) = \left(\frac{2}{3}\cdot x_{2} + \frac{1}{3} \cdot x_{1}, \frac{2}{3}\cdot y_{2} + \frac{1}{3} \cdot y_{1} \right)$

Step-by-step explanation:

Let be $A = (x_{1}, y_{1})$ , $B = (x_{3}, y_{3})$ and $C = (x_{2}, y_{2})$ . The ratio is:

$\frac{(x_{3}-x_{1},y_{3}-y_{1})}{(x_{2}-x_{3},y_{2}-y_{3})} = 2$

After some algebraic handling:

$(x_{3}-x_{1}, y_{3}-y_{1}) = 2 \cdot (x_{2}-x_{3},y_{2}-y_{3})$

$(x_{3}-x_{1}, y_{3}-y_{1}) = (2\cdot x_{2} - 2\cdot x_{3}, 2\cdot y_{2} - 2\cdot y_{3})$

$(3\cdot x_{3}, 3\cdot y_{3}) = (2\cdot x_{2} + x_{1}, 2\cdot y_{2} + y_{1})$

$3\cdot (x_{3}, y_{3}) = (2\cdot x_{2} + x_{1}, 2\cdot y_{2} + y_{1})$

$(x_{3},y_{3}) = \frac{1}{3}\cdot (2\cdot x_{2}+x_{1}, 2\cdot y_{2}+y_{1})$

The position of point B is:

$(x_{3}, y_{3}) = \left(\frac{2}{3}\cdot x_{2} + \frac{1}{3} \cdot x_{1}, \frac{2}{3}\cdot y_{2} + \frac{1}{3} \cdot y_{1} \right)$

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