What is the solution of this system of equations? x+5y=10 3x+y=16 a) x=0 y=2 b)x=5 y=1 c) x=3 y=7 d) x=-10 y=4

{x = 5 , y = 1 thus the Answer is B

Step-by-step explanation:

Solve the following system:

{x + 5 y = 10 | (equation 1)

{3 x + y = 16 | (equation 2)

Swap equation 1 with equation 2:

{3 x + y = 16 | (equation 1)

{x + 5 y = 10 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{3 x + y = 16 | (equation 1)

{0 x+(14 y)/3 = 14/3 | (equation 2)

Multiply equation 2 by 3/14:

{3 x + y = 16 | (equation 1)

{0 x+y = 1 | (equation 2)

Subtract equation 2 from equation 1:

{3 x+0 y = 15 | (equation 1)

{0 x+y = 1 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 5 | (equation 1)

{0 x+y = 1 | (equation 2)

Collect results:

 {x = 5 , y = 1

14 socks.

Step-by-step explanation:

30 socks in total. I think there is a 60% chance you will pull out a black sock??? But that doesn't matter. What if you were really unlucky and you pulled out all the navy socks? Then the answer would be 14 socks. To be CERTAIN, you want to pull out at least 14 socks. 12 socks for the navy. and 2 black socks.