What is the solution set of the quadratic equation –x2 + 6x – 8 = 0 ?

(2,6) and (-1,3)

Step-by-step explanation:

Hi there!

We're given the system of equations:

y=x+4

y=x²+2

and we need to solve the system

You may first notice that both equations are equal to y, so we can set them to equal each other via a property known as transitivity (if a=b and b=c, then a=c)

x²+2=x+4

subtract x from both sides

x²-x+2=4

subtract 4 from both sides

x²-x-2=0

we can factor the polynomial

the numbers that add up to -1 and multiply to get -2 are -2 and 1

(x-2)(x+1)=0

solve

x=2, x=-1

both values of x work- so we'll have 2 solutions in this case

now we need to solve for y; we can do this by substituting the value of x into one of the equations to solve for y

let's use y=x+4

so if we'll use x=2,

y=2+4

y=6

one solution will be (2,6)

and if we use x=-1

y=-1+4

y=3

and the other will be (-1,3)

Hope this helps! :)