ochoamiguel46
30.01.2020 •
Mathematics
What is the solution to log(x/2)+log(20/x^2)
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Ответ:
log(x/2) + log(20/x^2)
= log(x/2) + log 20 - log (x-2) [ becuase log a/b = log a - log b]
= log 20
= 1.301 to nearest thousandth
Ответ:
As written in the question Abbie, Chloe, and Xander are playing a dice game.
They are playing with two dices.
Rules are
Same number on both dice=+3
Different numbers, with an even sum=+1
An odd sum=-2
After five rounds score of Chloe=+1
→1=3+1+(-2)+(-2)+1
⇒ Same number on both dice ( in first throw)+Different numbers ,with an even sum (in second throw)+An odd sum(third throw)+An odd sum(fourth throw)+Different numbers ,with an even sum (in fifth throw)
As you can alter the arrangement ,In each case you will get sum as(+1), as integers Satisfy both Commutativity and Associativity with respect to addition.