What is the standard deviation of the following test scores? round your answer to the nearest hundredth. 82, 76, 93, 82, 73, 80

First we find the mean (or the average)...
average : (82 + 76 + 93 + 82 + 73 + 80 / 6) = 486/6 = 81

now we subtract the average from every data pointthen square the result
82 - 81 = 11^2 = 1
76 - 81 = -5-5^2 = 25
93 - 81 = 1212^2 = 144
82 - 81 = 11^2 = 1
73 - 81 = -8-8^2 = 64
80 - 81 = -1-1^2 = 1

now we find the mean (or average) of those numbers
(1 + 25 + 144 + 1 + 64 + 1) / 6 = 236/6 = 39.33

that is ur varianceto find the standard deviation, take the square root of ur variance

square root 39.33 = 6.27 <==

When forming a perfect square trinomial you need to "complete the square".
All of the steps to completing the square when solving an equation:
1.  The leading coefficient must be 1.
2.  Divide b by 2.
3.  Square (b/2)
4.  Add (b/2)^2 to both sides to keep the polynomial balanced.
5.  You can now write the perfect square trinomial and solve.

x^2 - 3x
-3/2
(-3/2)^2 = 9/4 = 2 1/4
LETTER B