Mathematics: What is the value of 2/3 rs if r= -6/7 and s= --3/10

LAST OPTION.Step-by-step explanation: Remember that: Then, you need to rewrite : Applying the identities, you get: Finally, you must simplify. Then:...

What is the value of 2/3 rs if r= -6/7 and s= --3/10 - id2367318445512, Idontreallycare16

Ответ:

jona187

06.02.2022

Mathematics

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$r = - \frac{6}{7} \\$

$s = - \frac{3}{10} \\$

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$\frac{2}{3} rs = \frac{2}{3} \times ( - \frac{6}{7} ) \times ( - \frac{3}{10} ) = \\$

$\frac{3 \times 2 \times 3 \times 2}{3 \times 7 \times 5 \times 2} = \frac{2 \times 3}{7 \times 5} = \frac{6}{35} \\$

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Ответ:

rebeccathecatt

18.09.2021

Mathematics

LAST OPTION.

Step-by-step explanation:

Remember that:

$tan(x)=\frac{sin(x)}{cos(x)}$

$\frac{cos(x)}{sin(x)}=cot(x)=\frac{1}{tan(x)}$

$sin(x\±y) = sin(x)cos(y)\±cos(x)sin(y)\\\\cos(x\±y) =cos(x)cos(y)\± sin(x)sin (y)$

$sin(90\°)=1\\cos(90\°)=0$

Then, you need to rewrite tan(90-A) :

$tan(90-A)=\frac{sin(90-A)}{cos(90-A)}$

Applying the identities, you get:

$tan(90\°-A)=\frac{sin(90\°)cos(A)-cos(90\°)sin(A)}{cos(90\°)cos(A)-sin(90\°)sin(A))}$

Finally, you must simplify. Then:

$tan(90\°-A)=\frac{(1)cos(A)-(0)sin(A)}{(0)cos(A)-(1)sin(A))}\\\\tan(90\°-A)=\frac{cos(A)}{sin(A)}\\\\tan(90\°-A)=\frac{1}{tan(A)}$

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What is the value of 2/3 rs if r= -6/7 and s= --3/10

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