What is the value of h(a) if h(x)=x to the power of two+4x-7

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Ответ:

Franklyn3220

26.09.2020

Mathematics

$y= 7\sqrt{2}$ units

Step-by-step explanation:

Using tangent ratio:

$\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}}$

As per the statement:

In the given right angle triangle.

First find x:

Using tangent ratio:

$\tan 45^{\circ} = \frac{7}{x}$

$1 = \frac{7}{x}$

⇒x = 7 units

We have to find the value of y:

Using Pythagoras theorem;

$\text{Hypotenuse side}^2=\text{opposite side}^2+\text{Adjacent side}^2$

Substitute the given values we have;

y^2 = 7^2+7^2

⇒ y^2 = 49+49 = 98

⇒ $y = \sqrt{98} = \sqrt{49 \cdot 2} = \sqrt{7^2 \cdot 2}$

⇒ $y = 7\sqrt{2}$ units

Therefore, the value of y is, $7\sqrt{2}$ units

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