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smann211
02.07.2019 •
Mathematics
What is the vertex of this quadratic function? f(x) = 10x2 + 5x − 7 a. (0.25, -5.250) b. (0.25, -7.625) c. (-0.25, -5.250) d. (-0.25, -2.525) e. (-0.25, -7.625)
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Ответ:
E
Given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
The x-coordinate of the vertex is
y = 10x² + 5x - 7 is in standard form
with a = 10, b = 5 and c = - 7, hence
Substitute this value into the equation for y-coordinate
y = 10 (-
)² + 5 (-
) - 7
=
-
- 7
=
-
-
= - ![\frac{61}{8}](/tpl/images/0042/9609/f46e3.png)
vertex = (- 0.25, - 7.625 ) → E
Ответ: