denaemarie02
08.07.2019 •
Mathematics
What is the volume of a tank that can hold 18 754 kg of methanol whose density is 0.788g/cm3
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Ответ:
(0.788) = (18.754) / V
0.788V = 18.754
V = (18.754) / (0.788)
V = 23.799
Ответ:
416.7
Step-by-step explanation: