What is the zero of the function f(x)=1/8x^2-x+2

x = 4  

Step-by-step explanation:

ƒ(x) = ⅛x² - x + 2 = 0

        x² - 8x + 16 = 0

We must find two numbers whose product is 16 and whose sum is -8.

A little trial and error gives us -4 and -4. We can factor the expression as

(x - 4)(x - 4) = 0 or

      (x - 4)² = 0

         x - 4 = 0

              x = 4

The zero of the function is x = 4.

The graph of ƒ(x) just touches the x-axis at (4, 0).