Mathematics: What is y=x^4/x^3 when values of x= {-2, 0, 3, 5, 7}

Irrational, it ends up equaling -19....

What is y=x^4/x^3 when values of x= {-2, 0, 3, 5, - id43203573504187, uticabadgirl

nett4386

08.01.2022

For this case we have a function of the form y = f (x) where:

$f (x) = \frac {x ^ 4} {x ^ 3}$

We simplify eliminating common terms of the numerator and denominator:

f (x) = x

We must find the values of the function when:

x = {-2, 0, 3, 5, 7}

So, we have:

For x = -2 :

f (-2) = - 2

For x = 0

f (0) = 0

For x = 3

f (3) = 3

For x = 5

f (5) = 5

For x = 7 :

f (7) = 7

Thus, the values of the function are:

y = {-2, 0, 3, 5, 7}

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