Mathematics: What number must be added to x^2+6x+7 to form a perfect square

What number must be added to x^2+6x+7 to form

Ответ:

stusullivanriley

12.03.2022

Let the number be k,

Then adding to the expression we have,

${x}^{2} + 6x + 7 + k$
For this to be a perfect square, the discriminant must be zero.

We have,

a=1, b=6, c=7+k

${b}^{2} - 4ac = 0$

This implies that

${6}^{2} - 4(1)(7 +k ) = 0$
36 - 28 - 4k = 0

hence the number to be added is 2

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Ответ:

naterasjen6531

30.07.2022

Mathematics

-3>-4 because the number line shows it going to the right side which means the number is bigger then -4 so the only bigger answer is -3 and is correct

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What number must be added to x^2+6x+7 to form a perfect square

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